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Going to be putting 8's in there... Gotta fit somehow.
At 8 Ohms yes, at four Ohms 2.81 V is two watts. V=IR which is voltage = current times resistance. Solve for I and multiply by V to get watts (Power=IV). And then you'll see that the nominal impedance makes a big difference in the actual sensitivity and # of ways you can wire the driver up to your amp(s).Originally Posted by I800C0LLECT
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