Pass A: Spins its tires excessively. Using arbitrary numbers, the car passes 500 feet at 60 MPH and no longer has enough power to spin its tires.
Pass B: Less wheelspin results in a better launch. The car passes the 500 foot mark at 70MPH. Clearly this pass will result in a faster trap speed because the car is moving faster at the same distance.
Your logic is the opposite. Please explain where I am wrong.
Your scenario doesn't work. When spinning your RPMs are up. Higher RPMs equals more MPH. If I had more time I could try to explain it yet again.
Just quickly, higher rpms equals higher in power band at a shorter point on the track equals more mph at end of track. SIMPLE
2011 Mitsubishi Lancer GTS - DD mode
1991 Mitsubishi 3000GT - Many mods to come